Okay so now we want to pick up where we left off and jump straight into our free body diagrams in case
I'm going to look at MEMBER A B first because I one determine the horizontal reaction an A and the sheer
force or by point B.
And taken to some of the moments point a first.
So theby lower is gonna be seven point to kill in humans in the direction shell which means hey J.
Therefore Hey Jay is going to be seven point two.
Also in the direction it was shot.
Jopling aunt to member C D.
So taken soon a moment point D.
And so v.c. Lower is seven point four six kilotons.
Therefore Hage D is also seven point forty six because we most have horizontal force equilibrium both
of those are in the directions depicted on the free body diagram.
And finally moving on to member ABC.
Case taken some of the moments about point B to determine vcl.
And so the ecl is equal to sixty one point six eight killer nations.
Some of the forces in the wider action must also equals zero.
And so VB or he will a sixty three point three two kilotons.
Onslaught rigs.
Okay.
The last thing you want to do for this member is determined.
Where in the stands is that Max moment occur and what is its value.
So first of all the max moment with we've used technique many many times now at this stage.
The max moment is at let's take the shear on the left which is going to be 60 No.
It's going to be sixty three point three two so it's six sixty three points a treat to divide that weight
25 that's gonna be two point five three metres.
So that's the maximum bending moment occurs at elsewhere that sheer force is zero.
And that's to the right of B.
Case We know where to make our course.
And so taking the suit the moment that caught.
And so Max
is equal to fifty three point one eight till noon meters causing tension on the bottom.
Okay so the last thing to do at this stage is simply summarize all of that information into the relevant
diagrams.
So starting off with the sheer force diagram.
And simply plotting on our values.
Okay.
And moving on to the bending moment diagram.
And finally the deflective shape.
Summarizing the reactions.
Now we can work out our qualitative deflected shape.
So what we're doing here is combining the information embedded in the bending moment diagram as to which
side of the element is experiencing tension that townsends which way our curve goes.
And we also know that the structure sways to the left so we can combine those two information sources
to sketch out of our deflected shape.
So looking at member C D the right hand vertical element First we can see that there is tension on the
right hand side of that element for its full length.
So that means that it curves over to the left with tension on the right hand side.
So.
And that makes sense because we know it sways to the left.
Now.
Again the left hand member has tension on the top bracket on the left.
Switching to tension on the right at the bottom half so that fits in with how we expect this thing to
go.
We think it's gonna do something like this.
Okay so we're gonna have a point of counter Fletcher at the point of zero moment and that's where we
go from tension on the outside to tension on the inside and then structure our horizontal structure
has tension on the top at either end and tension on the bottom in the middle.
So that's going to look something like this.
A point of counter lecture here and here so tension on the bottom and on the target.
And yet their intention on the top.
So that gives us an idea of how we expect our structure to deflect.
So in those three diagrams essentially we have wrapped OK summarized our complete analysis for that
sway frame.