This frame is very similar to a frame we have analyzed previously Except now we have a raw deal and
so we're dealing with as sway from stage one.
Analysis is complete because again we have tackled this problem or this structure in a previous work
example.
So when we did that we had a pain support at points.
And previously we've worked out that the propping force developed at that pin supports fifty eight point
five three clinicians.
So here we're going to jump straight into the stage to analysis which involves applying P E with a fifty
eight point five three collisions in the opposite direction so we can jump straight in to stage two.
So we'll apply in our she sway Delta prime and get the corresponding
sway force peak right so graphically what we're going to do can be represented as follows.
So going on to work at her arbitrary extend moments.
Looking at member B E.
First of all.
Looking at member C F.
And the last member in which our sway will induce bending moments is member C G.
OK.
Condensing those down into more manageable numbers.
So looking for a close common multiple is 48.
OK.
Now we can do our moment distribution with those arbitrary fixed and moments.
OK.
We can label these as our arbitrary state two moments.
Now as usual we go and calculate p prime that generated those moments.
So looking at member of B E first.
And if we take these some of the moments very pointy we will eventually evaluate that b v B lower is
equal to eight point over one plus thirteen point one eight.
I'll avoid a byte for all I'm doing is skipping one or two steps into the development of that equation
with that's what we end up with.
So with the B lower will be five point three killiney Happens in the direction show.
Moving on to member C F.
So these C lower is going to be the 10 point set and one plus nine point three three I'll divide by
the e6 and we see lower.
Again that's just taking more it's about point f so obviously lower is going to be three point three
for kill and hardens in the direction shell and a last member we have to look at in order to determine
peep prime is member at C G.
And so with each c opener.
In this case is going to be the moment which is eleven point nine six.
Divide that by the length the man broaches three meters and so.
The C.
Opera is equal to three point ninety nine.
Kill innocents.
That allows us to determine p prime.
So therefore p prime and then in brackets to remind ourselves p prime that causes Delta prime that causes
Delta prime is equal to my five point three plus three point three four plus three point ninety nine
which is equal to twelve point six three killens and so straight away in my sway factor the amapa which
I have to scale my arbitrary stage to moments in order to determine actual sway.
Stage 2 moments to sway factor is equal to Blanda which is P over p prime which is simply fifty eight
point five three over twelve point six three.
So lambda is four point sixty three.
Okay great.
All right now we're at it at a position where we can carry over superimposition whereby we're superimposing
these stage one and stage two moments together on top of each other if you like simply adding them together.
So the logical way to do this is to set those in a table.
Okay so that wraps up to stage to analysis somehow we've determined the ending moments at those key
join locations in our frame.
And so as usual at this point we should look start looking at some free body diagrams to determine the
remaining unknown internal shears and bending moment in order to flesh out our diagrams.
And so really that's a revision of fairly basic material so the new stuff that we've introduced in this
course has been wrapped up in this video.
Nevertheless to wrap up the question to finish this thing out we will in the next video walk away through
those free body diagrams and develop the sheer force diagram the bending moment diagram and the qualitative
deflected shape.